Answer:
Some wire is used to make 3 rectangles: A, B, and C. Rectangle 's dimensions are 3 cm larger than Rectangle A's dimensions, and Rectangle C's dimensions are cm larger than Rectangle B's dimensions. Rectangle A is 2 cm by 3 cm. a. What is the total area of all three rectangles?
The answer is 30.36cm²
Step-by-step explanation:
Rectangle A dimensions
[tex]L = 3\frac{1}{5} cm[/tex] [tex]= \frac{16}{5}[/tex]
B = 2cm
Rectangle B dimensions
Length Breath
[tex]L + \frac{3}{5}[/tex] [tex]B + \frac{3}{5}[/tex]
[tex]\frac{16}{5} +\frac{3}{5}[/tex] [tex]2+\frac{3}{5}[/tex]
[tex]\frac{19}{5}cm[/tex] [tex]\frac{13}{5} cm[/tex]
Rectangle C dimensions
[tex]\frac{19}{5} +\frac{3}{5}[/tex] [tex]\frac{13}{5} +\frac{3}{5}[/tex]
[tex]\frac{22}{5}[/tex] [tex]\frac{16}{5}[/tex]
Area of rectangle A
16 / 5 × 2 = 32/5 cm²
Area of rectangle B
[tex]= \frac{19}{5} \times \frac{13}{5} \\\\=\frac{247}{25} cm^2[/tex]
Area of rectangle C
[tex]\frac{22}{5} \times \frac{16}{5} \\\\= \frac{352}{25}[/tex]
Total area =
[tex]\frac{32}{5} + \frac{247}{25} + \frac{352}{25} \\\\= 30.36cm^2[/tex]
