contestada

A liquid of density 1190 kg/m3 flows steadily through a pipe of varying diameter and height. At Location 1 along the pipe, the flow speed is 9.63 m/s and the pipe diameter d1 is 12.7 cm. At Location 2, the pipe diameter d2 is 16.3 cm. At Location 1, the pipe is Δy=9.27 m higher than it is at Location 2. Ignoring viscosity, calculate the difference ΔP between the fluid pressure at Location 2 and the fluid pressure at Location 1.

Respuesta :

Rau7star

Answer:

143kW

Explanation:

Given:

[tex]v_1[/tex]=9.63m/s

Δy=[tex]z_2-z_1[/tex]=9.27 m

density'ρ'=1190 kg/m3

According to Bernouilli  :

p/ρ + gz + (1/2)v² = constant.

Also vA = constant, so vr² = constant.

Hence, at location 2, the speed is (9.63 m/s)(12.7²/16.3²),

that is, [tex]v_2[/tex] = 5.85 m/s.

[tex]p_2-p_1[/tex] = ρ { g([tex]z_1-z_2[/tex]) + ([tex]\frac{1}{2}[/tex])[[tex]v_1^2-v_2^2[/tex]] }

            = (1190 kg/m³) [9.8 m/s² (9.27 m) + ([tex]\frac{1}{2}[/tex])(9.63² - 5.85 ²)m²/s²]

[tex]p_2-p_1[/tex] =143kW

Otras preguntas