Suppose a normal distribution has a mean of 266 and a standard deviation of

12. What is P(x > 278)?

O A. 0.16

O B. 0.475

O c. 0.84

O D. 0.975

Respuesta :

Answer:

P(x>278) is 0.16

Step-by-step explanation:

We are given that a normal distribution has a mean of 266 and a standard deviation of  12.

Mean = [tex]\mu =266[/tex]

Standard deviation =[tex]\sigma = 12[/tex]

We are supposed to find P(x > 278)

So, Formula : [tex]Z=\frac{x-\mu}{\sigma}[/tex]

[tex]Z=\frac{278-266}{12}[/tex]

Z=1

Refer the z table for p value

p value = 0.8413

P(x<278) is 0.84

P(x>278)=1-P(x<278)=1-0.84=0.16

Option A is true

Hence P(x>278) is 0.16

Answer:

A. 0.16

Step-by-step explanation:

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