Answer:
[tex]\huge \boxed{y \leq \frac{-4x+15}{3} }[/tex]
[tex]\rule[225]{225}{2}[/tex]
Step-by-step explanation:
[tex]4x + 3y \leq 15[/tex]
Subtracting 4x from both sides.
[tex]3y \leq 15-4x[/tex]
Dividing both sides by 3.
[tex]\displaystyle y \leq \frac{15-4x}{3}[/tex]
[tex]\rule[225]{225}{2}[/tex]
