Answer:
yes since p value = 0
Explanation:
mean value for high school students (M) = 7.1
standard deviation = 1
sample size of college students ( n ) = 41
sample mean of college students ( X )= 6.6
applying the test statistic to determine the p value
= sample mean of college students ( X ) - M ( mean ) / [tex]\frac{1}{\sqrt{n} }[/tex]
= (6.6 - 7.1 ) ( [tex]\frac{1}{\sqrt{41} }[/tex] )
= - 0.5 / 0.1561 = -3.20
therefore p value = 0 hence we can conclude