A solenoid has 450 loops, each of radius 0.0254 m. The field increases from 0T to 3.00 T in a certain amount of time. If 15.6 V of EMF are generated in the coil, how much time elapsed? (Hint: What is the area of a circle?) (Unit = s)

Respuesta :

Answer:

0.175s

Explanation:

To find the time elapsed you use the following formula:

[tex]emf=-N\frac{d\Phi}{dt}=-N\frac{d(AB)}{dt}[/tex]

N: turns

A: cross area of the loop

B: magnitude of the magnetic field

for discrete changes and for a constant area A you have:

[tex]emf=-N(\pi r^2)\frac{\Delta B}{\Delta t}[/tex]

You replace the values of the parameters to calculate the elapsed time:

[tex]\Delta t=-N\frac{(\pi r^2)\Delta B}{emf}\\\\\Delta t=-(450)\frac{(\pi(0.0254m)^2)(3.00T-0.00T)}{15.6V}\\\\\Delta t=0.175s[/tex]

hence, the elapsed time is 0.175s