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A student prepares a solution of sodium chloride by dissolving 116.9 g of NaCl into enough water to make 1.00 L of solution. How would the student properly label this solution?
Question 20 options:


2.00 M/L NaCl


116.9 M NaCl


116.9 M NaCl


116.9 g / L NaCl

Respuesta :

jamesesther1234

Answer:

The accurate label for the solution is 2.00 mol/L NaCl.

Explanation:

Molrity = mass ÷ molar mass

Molar mass of NaCL = 58.44 g/mol

Weighed mass = 116.9g

⇒ Molarity of the solution = [tex]\frac{116.9}{68.44}[/tex] = 2.0M

Therefore, the accurate label for the solution is 2.00 mol/L NaCl.

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