Answer:
New volume of the balloon will be 28.4 L.
Explanation:
As the amount of gas and pressure of the gas remains constant therefore in accordance with Charles's law:
[tex]\frac{V_{1}}{T_{1}}=\frac{V_{2}}{T_{2}}[/tex]
where [tex]V_{1}[/tex] and [tex]V_{2}[/tex] are volume of gas at [tex]T_{1}[/tex] and [tex]T_{2}[/tex] temperature (in kelvin scale) respectively.
Here [tex]V_{1}=25.0L[/tex], [tex]T_{1}=(273+20)K=293K[/tex] and [tex]T_{2}=(273+60)K=333K[/tex]
So [tex]V_{2}=\frac{V_{1}T_{2}}{T_{1}}=\frac{(25.0L)\times (333K)}{293K}[/tex] = 28.4 L
So new volume of the balloon will be 28.4 L.
