Answer:
a) f = 17,898 cm , b) P = 5.58D
Explanation:
a) For this exercise we must use the constructor equation
1 / f = 1 / p + 1 / q
where f is the focal length and p, q are the distance to the object and the image, respectively
in this case they tell us that the distance to the point of near vision is q = 70.4 cm, here the image must be so that the person can see it normally
1 / f = 1 / 24.0 + 1 / 70.4
1 / f = 0.05587
f = 17,898 cm
b) the power of a lens is defined as the inverse of the focal length in meters
P = 1 / d
p = 1 / 0.17898
P = 5.58D
