Respuesta :
Answer:
Explanation:
We shall use the stefan's law to solve the problem .
E = eA σ T⁴
E is heat radiated per second , e is emissivity , A is area , σ is stefan's constant and T is temperature of hot surface.
Substituting the given values,
10.3 = .235 x 1.77 x 5.67 x 10⁻⁸ T⁴
T⁴ = 4.367 x 10⁸
1.4456 x 10²
= 144.56 K
The Stefan's law describes the power of black body radiation in terms of its temperature. The temperature of the robot HooRU that has been lost in the space is 144.56 K.
The temperature can be determined by the Stefan's law
[tex]\bold {E = eA\ \sigma\ T^4}[/tex]
Where
E - heat radiated per second = 10.3
e- emissivity = 0.235
A - surface area = 1.77 m2
σ - Stefan's constant = 5.67x10⁻⁸
T - temperature of hot surface
Put the values in the formula,
[tex]\bold {10.3 = 0 .235 \times 1.77 \times 5.67x10^-^8 \times T^4}\\\\\bold {T^4 = 4.367 x 10^8 }\\\\\bold {T= 144.56\ K}[/tex]
Therefore, the temperature of the robot HooRU that has been lost in the space is 144.56 K.
To know more about Stefan's law
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