Answer:
0.18 mol
Explanation:
Given data
Step 1: Convert the temperature to Kelvin
We will use the following expression
K = °C + 273.15
K = 25°C + 273.15
K = 298 K
Step 2: Convert the pressure to atmospheres
We will use the relation 1 atm = 101.3 kPa.
[tex]100.4kPa \times \frac{1atm}{101.3kPa} = 0.991atm[/tex]
Step 3: Calculate the moles of the gas
We will use the ideal gas equation.
[tex]P \times V = n \times R \times T\\n = \frac{P \times V}{R \times T} = \frac{0.991atm \times 4.5L}{\frac{0.0821atm.L}{mol.K} \times 298K} = 0.18 mol[/tex]
