Answer:
The radius of the cone(r) =5.07 inches
Step-by-step explanation:
Step(i):-
Given the Volume of a cone is 108 cubic inches
Given height of the cone is '4' inches
volume of the cone
The volume of the cone is defined by
[tex]V = \frac{1}{3} \pi r^{2} h[/tex]
'r' is the radius of the cone
'h' is the height of the cone
Step(ii):-
V = 108 cubic inches
h = '4' inches
[tex]V = \frac{1}{3} \pi r^{2} h[/tex]
[tex]\frac{1}{3} \pi r^{2} X 4 =108[/tex]
[tex]4\pi r^{2} = 108X3[/tex]
the value of π = 3.14
[tex]r^{2} = \frac{108X3}{4X3.14}[/tex]
[tex]r^{2} =25.79[/tex]
[tex]r = \sqrt{25.79} =5.07 inches[/tex]
Conclusion:-
The radius of the cone 'r' = 5.07 inches
