The wall has dimensions of 100 ft x 10 ft including window and door areas. The wall has a total window area of 80 ft2 and a door (8 ft x 2.5ft). The heat-transfer coefficients are 0.2 Btu/hr-ft2 –F for wall, 0.1 Btu/hr-ft2 –F for window, and 0.1 Btu/hr-ft2 –F for door. Determine the effective overall heat-transfer coefficient for the combination, U

Respuesta :

Answer:

The effective overall heat transfer coefficient for the combination, [tex]U = 0.19 Btu/hr-ft^2 -F[/tex]

Explanation:

According to the question, the total area includes the areas of the wall, window and door.

Total area, A = 100 * 10 = 1000 ft²

Area of the window, [tex]A_{wind} = 80 ft^2[/tex]

Area of the door, [tex]A_{d} = 8 * 2.5 = 20 ft^2[/tex]

Area of the wall, [tex]A_{wall} = A - (A_{d} + A_{wind} )[/tex]

[tex]A_{wall} = 1000 - ( 80 + 20)\\A_{wall} = 900 ft^2[/tex]

Heat transfer coefficients:

For wall, [tex]h_{wall} = 0.2Btu/hr-ft^2-F[/tex]

For window,  [tex]h_{wind} = 0.1Btu/hr-ft^2-F[/tex]

For door,  [tex]h_{d} = 0.1Btu/hr-ft^2-F[/tex]

To get the overall heat - transfer coefficient for the combination:

[tex]AU = A_{wall} h_{wall} + A_{wind} h_{wind} + A_{d} h_{d}\\1000U = (900*0.2) + (80*0.1) + (20*0.1)\\1000U = 190\\U = 190/1000\\U = 0.19 Btu/hr-ft^2 -F[/tex]