The equation in the polar form is z = 3√2(cos π/4 + isin π/4)
The numbers that can be represented in the form of a+ib , where a nd b are real numbers and i is the imaginary number can be represented by √-1 .
the complex number z=-3+3i in polar form
Since the real part and imaginary part of the complex number z = 3 + 3i are positive, z lies in the first quadrant.
we have to find z and [tex]\rm \theta\\[/tex]
|Z| = [tex]\rm \sqrt{(a^2 +b^2)}[/tex]
=[tex]\rm \sqrt{3^2+3^2}[/tex]
= √18
|Z| =3√2
θ = tan-1(b / a)
θ = tan-1(3 / 3)
θ = tan-1(1)
θ = π/4
The equation in the polar form is
z = 3√2(cos π/4 + isin π/4)
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