How much heat will be released if 9.75 g of aluminum reacts with excess ammonium nitrate (NH₄NO₃) according to the following equation? 2 Al (s) + 3 NH₄NO₃ (s) ---> 3 N₂ (g) + 6 H₂O (g) + Al₂O₃ (s) ΔH = -2030 kJ *