What is the equation of the trend line in the scatter plot? Use the two yellow points to write the equation in slope-intercept form.
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Answer:
The slope intercept form
[tex]y= \frac{6}{5} (x) -\frac{7}{5}[/tex]
Step-by-step explanation:
Step(i)
Given scatter plot of yellow dot points are
(2,1) and (7,7)
The slope intercept form is y = mx +c
(x₁ , y₁)= (2,1) and (x₂ ,y₂) = (7,7)
slope of the line
[tex]m = \frac{y_{2} -y_{1} }{x_{2} -x_{1} } = \frac{7-1}{7-2} = \frac{6}{5}[/tex]
step(ii):-
The point slope form
y -y₁ = m (x -x₁)
[tex]y-1 = \frac{6}{5} (x-2)[/tex]
On simplification, we get
5(y-1) = 6(x-2)
[tex]y-1 = \frac{6}{5} (x-2)[/tex]
[tex]y = \frac{6}{5} (x-2) +1[/tex]
[tex]y= \frac{6}{5} (x) -\frac{12}{5} +1[/tex]
[tex]y= \frac{6}{5} (x) -\frac{7}{5}[/tex]
Final answer:-
The slope intercept form
[tex]y= \frac{6}{5} (x) -\frac{7}{5}[/tex]