Answer:
[tex]\Delta T=194^oC[/tex]
Explanation:
Hello,
In this case, the relationship between the mass, heat, temperature and heat capacity id given by:
[tex]Q=mCp\Delta T[/tex]
In such a way, the temperature change results:
[tex]\Delta T=\frac{Q}{mCp}=\frac{480.0cal}{75.0g*0.033cal/(g^oC)} \\\\\Delta T=194^oC[/tex]
Clearly it is a positive change which means the temperature increases as heat is added.
Regards.
