Answer:
[tex]\large \boxed{\text{52.27 g}}[/tex]
Explanation:
1. Molar masses
(a) CO₂
1 C = 1 × 12.01 u = 12.01 u
2 O = 2 × 16.00 u = 32.00 u
TOTAL = 44.01 u
(b) O₂
2 O = 2 × 16.00 u = 32.00 u
2. Mass of oxygen produced
We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.
Mᵣ: 44.01 32.00
CO₂ ⟶ C + O₂
m/g: 71.89
So, 32.00 g of oxygen form from 44.01 g of CO₂
[tex]\text{Mass of O}_{2} = \text{71.89 g CO}_{2} \times \dfrac{\text{32.00 g O}_{2}}{\text{44.01 g CO}_{2}} = \textbf{52.27 g O}_{2}\\\\\text{The mass of O$_{2}$ produced is $\large \boxed{\textbf{52.27 g}}$}[/tex]
