Please helppppppppppo
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Answer:
A 62°
Step-by-step explanation:
By inscribed angle theorem:
[tex] m\angle MQP = \frac{1}{2} (84° + m\overset{\frown}{NP}) \\
73° = \frac{1}{2} (84° + m\overset{\frown}{NP}) \\
73° \times 2= 84° + m\overset{\frown}{NP} \\
146° = 84° + m\overset{\frown}{NP} \\
146° - 84° = m\overset{\frown}{NP} \\
m\overset{\frown}{NP} = 62°[/tex]