Answer:
The maximum height of the arrow is 14.73 m.
Step-by-step explanation:
The height of the arrow follows a parabolic path. Its height can be modeled by the function,
[tex]f(x)=-0.07x^2+1.5x+6.7[/tex] ......(1)
It is required to find the maximum height of the arrow
For maximum height, [tex]f'(x)=0[/tex]
i.e.
[tex]\dfrac{d(-0.07x^2+1.5x+6.7)}{dx}=0\\\\-0.14x+1.5=0\\\\0.14x=1.5\\\\x=\dfrac{1.5}{0.14}\\\\x=10.71\ m[/tex]
Put x = 10.71 m in equation (1). So,
[tex]f(x)=-0.07(10.71)^2+1.5(10.71)+6.7\\\\f(x)=14.73\ m[/tex]
So, the maximum height of the arrow is 14.73 m.
