A spring is attatched at one end to support B and at the other end to collar A, as represented in the figure. Collar A slides along the vertical bar between points C and D.

Part A when 0 = 28 degrees, what is the distance from point A to point B to the nearest tenth of a foot?

Part B When the spring is stretched and the distanced from point A to point B is 5.2 feet, what is the valuue of 0 to the nearest tenth of a degree?

A spring is attatched at one end to support B and at the other end to collar A as represented in the figure Collar A slides along the vertical bar between point class=

Respuesta :

Step-by-step explanation:

cos θ = 3 / AB

When θ = 28°:

cos 28° = 3 / AB

AB = 3 / cos 28°

AB ≈ 3.4

When AB = 5.2:

cos θ = 3 / 5.2

θ = cos⁻¹(3 / 5.2)

θ ≈ 54.8°

By applying trigonometry function:

A. Distance of point A to point B is: 3.4 ft

B. The value of ∅ is: 54.8°

Recall:

  • The trigonometry ratios to solve missing lengths or angles of a right triangle are: SOH CAH TOA.

The image given shows a right triangle.

Part A: Distance of point A to point B.

  • Reference angle (∅) = 28°
  • Hypotenuse = AB = ?
  • Adjacent = 3 ft

To find AB, apply the trigonometry function, CAH, which is:

cos ∅ = adj/hyp

  • Substitute

cos 28°= 3/AB

AB = 3/cos 28°

AB = 3.4 ft (nearest tenth of a foot)

Part B: Value of ∅ when AB = 5.2 ft.

∅ = ?

adj = 3 ft

hyp = AB = 5.2 ft

To find ∅ , apply the trigonometry function, CAH, which is:

cos ∅ = adj/hyp

  • Substitute

cos ∅ = 3/5.2

[tex]\theta = cos^{-1}(\frac{3}{5.2} )\\\\\mathbf{\theta = 54.8^{\circ}}[/tex](nearest tenth of degree).

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