Use the work shown below to write the equation for a line that passes through the points (−5, 0) and (−1, −8).

1. Use slope formula to find slope:

m = StartFraction negative 8 minus 0 Over negative 1 minus (negative 5) EndFraction = StartFraction negative 8 Over 4 EndFraction = negative 2

2. Substitute one point and slope into slope-intercept form to find the y-intercept:

0 = negative 2 (negative 5) + b. 0 = 10 + b. b = negative 10.

What is the equation of the line in slope-intercept form?
y = –10x – 2
y = –1x – 8
–8 = –2x – 1
y = –2x – 10

Respuesta :

Answer:

The equation of the line in slope-intercept form is: y = -2x - 10

Step-by-step explanation:

An equation for a line that passes through the points A = (−5, 0) and B = (−1, −8).

The formula to compute the slope, using two point is:

[tex]\text{Slope}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]

Compute the slope of the line as follows:

[tex]\text{Slope}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]

    [tex]m=\frac{-8-0}{-1+5}\\\\[/tex]

        [tex]=\frac{-8}{4}\\\\=-2[/tex]

The slope of the line is -2.

Compute the equation of the line as follows:

[tex](y-y_{1})=m\times (x-x_{1})[/tex]

   [tex]y-0=-2\times (x+5)[/tex]

         [tex]y=-2x-10[/tex]

The y-intercept of the line is -10.

The equation of the line in slope-intercept form is:

y = -2x - 10

Answer:

D.y = –2x – 10

Step-by-step explanation: