I BEG OF YOU, PLEASE HELP ME!!!!! My diploma is counting on it!!

Find the equation of the parabola that has zeros of x = -6 and x = 6 and a y-intercept
of (0,4).

A) y = -1/9(x^2 - 36)

B) y = -1/9x^2 - 4

C) y = 1/9(x^2 - 36)

D) y = 1/9x² - 36

Respuesta :

Answer:

A is correct

Step-by-step explanation:

A) y = -1/9(x^2 - 36)

The equation of the parabola that has zeros of x = -6 and x = 6 and a y-intercept of (0,4); y = -1/9(x^2 - 36). A is correct

What is a parabola?

Parabola is defined as the graph of a quadratic function that has something bowl-shaped.

We need to Find the equation of the parabola that has zeros of x = -6 and x = 6 and a y-intercept of (0,4).

If a quadratic equation is written in the form

[tex]y=a(x-h)^2 + k[/tex]

then it is called to be in vertex form. It is called because when you plot this equation's graph, you will see vertex point(peak point) is on (h,k)

(h, k) is the vertex of the parabola and (f, k) is the focus.

Thus, the equation of the parabola that has zeros of x = -6 and x = 6 and a y-intercept of (0,4);

A) y = -1/9(x^2 - 36)

Learn more about the parabola here:

brainly.com/question/8708520

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