Answer:
Check the explanation
Explanation:
cell CuE Ecell 0.337 (-0.14) Ecl0.477 V
Since [tex]E^o_{ cell } > 0[/tex] , the value of \Delta G^o will be negative.
[tex]\Delta G^o < 0[/tex]
[tex]\Delta G^o =-nFE^o_{ cell }.[/tex].....(1)
But
[tex]\Delta G^o =-RT ln K[/tex]......(2)
From (1) and (2)
[tex]\Delta G^o =-RT ln K=-nFE^o_{ cell }[/tex]
ln K =[tex]\frac{nFE^o_{ cell } }{RT }[/tex]
ln K =[tex]\frac{ 2 \times 96500 \times 0.477 }{8.314 \times \left ( 25+273.15 \right ) }[/tex]
ln K =37.139
K =[tex]1.3468 \times 10^{16}[/tex]
Hence, the value of the equilibrium constant is [tex]1.35 \times 10^{16}[/tex]
