Answer:
Slope = [tex]\frac{1}{5}[/tex]
Equation of the line is [tex]y=\frac{x}{5}[/tex]
Step-by-step explanation:
Given question is incomplete; find the complete question in the attachment.
Since the given line passes through two points (5, 1) and (10, 2),
Slope of the given line = [tex]\frac{(y_{2}-y_{1})}{(x_{2}-x_{1})}[/tex]
m = [tex]\frac{(2-1)}{(10-5)}[/tex]
m = [tex]\frac{1}{5}[/tex]
Since the given line passes through (10, 2), equation of the line will be
y - y' = m(x - x')
[tex]y - 2=\frac{1}{5}(x-10)[/tex]
[tex]y=2+\frac{x}{5}-2[/tex]
[tex]y=\frac{x}{5}[/tex]
Therefore, equation that can be used to find the distance y from the start after x minutes will be [tex]y=\frac{x}{5}[/tex]
