3. A student pushed a 10.0 kg box across a level, frictionless floor with an acceleration of 5.00 m/s.
Calculate the force the student applied to the box?
A. 0.500 N
B. 2.00 N
C. 15.0 N
D. 50.0 N

Respuesta :

pretty sure the answer is B

Taking into account the Newton's second law, the correct answer is option D): the force the student applied to the box is 50 N

Newton's Second Law, also called the Fundamental Law of Dynamics, indicates that: "The change in motion is directly proportional to the printed motive force and occurs according to a straight line along which that force is printed." This means that the acceleration of a moving object depends on the amount of force applied to it at a given moment, in order to modify its trajectory or speed.

Mathematically, Newton's second law is expressed as:

F= m×a

where:

  • F = Force [N]
  • m = Mass [kg]
  • a = Acceleration [m/s²]

In this case, you know:

  • F= ?
  • m= 10 kg
  • a= 5 m/s²

Replacing:

F= 10 kg× 5 m/s²

Solving:

F= 50 N

Finally, the correct answer is option D): the force the student applied to the box is 50 N

Learn more about the Newton's second law:

  • brainly.com/question/23845187?referrer=searchResults
  • brainly.com/question/13959891?referrer=searchResults
  • https://brainly.com/question/14713499