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Hugo plans to buy packs of baseball cards until he gets the card of his favorite player, but he only has enough
money to buy at most 4 packs. Suppose that each pack has probability 0.2 of containing the card Hugo is hoping
for.
Let the random variable X be the number of packs of cards Hugo buys. Here is the probability distribution for
X:
X = # of packs 1
P(X)
0.2
2
0.16
3
0.128
4
0.512
What is the probability that Hugo buys at most 3 packs of cards?

Respuesta :

Answer:

.36

Step-by-step explanation:

"Fewer than 3 packs of cards" means that he buys 1 or 2 packs.

Let's see how likely he is to buy 1 or 2 packs; then we add those probabilities:

.2+.16=.36

ajeigbeibraheem

The probability that Hugo buys at most 3 packs of cards is P(X ≤ 3) = 0.488

If X is the random variable that denotes the number of packs of cards Hugo buys,

Then, the probability that Hugo buys at most 3 packs of cards can be computed as:

P(X ≤ 3)  

The table given is expressed as:

X = # of packs         1           2           3           4

P(X)                          0.2      0.16       0.128     0.512

∴

  • P(X ≤ 3) = P(1) + P(2) + P(3)
  • P(X ≤ 3) = 0.2 + 0.16 + 0.128
  • P(X ≤ 3) = 0.488

Learn more about probability here:

https://brainly.com/question/23044118?referrer=searchResults

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