Answer:
Force, [tex]F=9.21\times 10^{-24}\ N[/tex]
Explanation:
Distance between proton is 0.005 m
It is required to find the force between two protons. Protons have of positive charge of [tex]1.6\times 10^{-19}\ C[/tex]. Two protons will have a force of repulsion between them. The force is given by :
[tex]F=\dfrac{kq^2}{r^2}\\\\F=\dfrac{9\times 10^9\times (1.6\times 10^{-19})^2}{(0.005)^2}\\\\F=9.21\times 10^{-24}\ N[/tex]
So, the force between two protons is [tex]9.21\times 10^{-24}\ N[/tex].
