Jessica has 20 pieces of candy in a bag: 2 mint sticks, 9 jelly treats, and 9 fruit tart chews. If she eats one piece every 10 minutes, what is the probability her first two pieces will both be jelly treats?

In this case what we must do is calculate the probability of eating a jelly treats first and then another jelly treats, being the final probability the multiplication of these events.

We know that there are 20 in total and that initially there are 9 jelly treats, so the first event is the probability:

9/20

And the second event, with one less in each, would be:

8/19

The final probability then:

9/20 * 8/19 = 0.1895

So the probability of this happening is 18.95%

samuelonum1 samuelonum1 · Answer 2 · 2020-05-18T03:17:41+02:00

Answer:

18/95

Step-by-step explanation:

Given data

2 mint sticks,

9 jelly treats, and

9 fruit tart chews.

Sample space = {2+9+9} = 20

N/B this is done without replacement since the candy are eaten Hence after each selection the candy and the sample size reduces

1.The probability of eating the first jelly treat = 9/20

2.The probability of eating the first jelly treat = 8/19

Hence the probability of her first two pieces will both

be jelly i= 9/20*8/19= 72/380

= 18/95