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Determine the discriminant for the quadratic equation 0=-2x2+3. Based on the discriminant value, how many real number solutions does the equation have? Discriminant = b2-4ac

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behshtashakari33

Answer:

Determine the discriminant for the quadratic equation 0 = –2x2 + 3. Based on the discriminant value, how many real number solutions does the equation have?  Remember that the discriminant is calculated using the coefficents a, b and c.  Given 0 = -2x^2 + 0x + 3, the coeff. are a=-2, b=0 and c=3.

The discriminant is b^2 - 4ac.  Here, the discriminant is 0^2 - 4(-2)(3) = 24.

Since the discriminant is positive, you have two real, unequal roots.

Step-by-step explanation:

The value of D is positive therefore, there are two real unequal roots and this can be determined by using the formula of the discriminant.

Given :

The quadratic equation is [tex]0 = -2x^2+3[/tex].

The following steps can be used in order to determine the total number of real solutions does the equation have:

Step 1 - Write the given quadratic equation.

[tex]0 = -2x^2+3[/tex]

Step 2 - The formula of the discriminant is given below:

[tex]D = b^2-4ac[/tex]

Step 3 - So, the value of 'a' is -2, the value of 'b' is 0, and the value of 'c' is 3.

[tex]D = (0)^2-4\times (-2)\times (3)[/tex]

[tex]D = 24[/tex]

The value of discriminant D is positive therefore, there are two real unequal roots.

For more information, refer to the link given below:

https://brainly.com/question/2263981

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