We have been given an equation [tex]0 = x^2-4x + 5[/tex]. We are asked to find the discriminant of our given equation.
We will use discriminant formula to solve our given problem.
[tex]D=b^2-4ac[/tex], where,
D = Discriminant,
b = Coefficient of x term,
a = Coefficient of [tex]x^2[/tex] term,
c = Constant.
[tex]D=(-4)^2-4(1)(5)[/tex]
[tex]D=16-20[/tex]
[tex]D=-4[/tex]
When D is less than 0, then equation has no real solutions.
When D is equal to 0, then equation one real solution.
When D is greater than 0, then equation has two real solutions.
Since [tex]-4[/tex] is less than 0, therefore, our given equation has no real solutions.
