3 semicircles are connected to 3 sides of a square. Each side of the square measures 4 centimeters. What is the area of the composite figure? (6π + 4) cm2 (6π + 16) cm2 (12π + 4) cm2 (12π + 16) cm2

Respuesta :

the square area is 4x4 is 16

each semicircle has a diameter of 4cm.

area of a semicircle is pi * r^2/2

3.14*2^2/2=6.28

since there are 45 sides of a square, 6.28x3=18.84

add 18.84 and 16.

34.84 is your answer.

The area of the composite figure which consist 3 semicircles and a square with 4 centimeters is (6π+16) cm².

What is the area of the semicircle?

The area of the semicircle is the space occupied by it. It can be given as,

[tex]A_s=\dfrac{d^2}{8}\pi[/tex]

Here, (d) is the diameter of the semicircle.

Each side of the square measures 4 centimeters. The area of the square is square of its side. Thus,

[tex]A_s=4^2\\A_s=16\rm\; cm^2[/tex]

3 semicircles are connected to 3 sides of a square. Thus, the diameter of the semicircle is equal to 4 cm. The area of 3 semicircles is,

[tex]A_{sc}=3\times\dfrac{(4)^2}{8}\pi\\A_{sc}=6\pi[/tex]

The area of the composite figure is,

[tex]A=A_s+A_{sc}\\A=16+6\pi\\A_s=(6\pi+16)\rm\; cm^2[/tex]

Thus, the area of the composite figure which consist 3 semicircles and a square with 4 centimeters is (6π+16) cm².

Learn more about the area of the circle here;

https://brainly.com/question/402655

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