Three out of nine students in the computer club are getting prizes for first, second, and third place in a competition. How many ways can first, second, and third place be assigned? 9 P 3 = StartFraction 9 factorial Over (9 minus 3) factorial 3 84 504 2048

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Answer:

B) 504

Step-by-step explanation:

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The number of ways first, second, and third can place be assigned = 504

What is permutation?

"It is a method of the number of ways a particular set can be arranged, where order of the arrangement matters."

What is the formula of permutation?

[tex]^nP_r=\frac{n!}{(n-r!)}[/tex]

What is n! ?

For a positive integer n,

n! = n × (n - 1) × (n - 2) × . . . × 2 × 1

For given question,

3 out of 9 students in the computer club are getting prizes for first, second, and third place in a competition.

We need to find the number of ways first, second, and third can place be assigned.

Here n = 9 and r = 3

Using permutation formula,

[tex]^9P_3\\\\=\frac{9!}{(9-3)!}\\\\ =\frac{9\times 8\times 7 \times 6!}{6!}\\\\ =9\times 8\times 7\\\\=504[/tex]

Therefore, the number of ways first, second, and third can place be assigned = 504

Learn more about the permutation here;

https://brainly.com/question/13387529

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