Answer: 1082 g of carbon dioxide are produced for every 350 grams of octane reacted in the engine
Explanation:
To calculate the moles :
[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]
[tex]\text{Moles of} C_8H_{18}=\frac{350g}{114g/mol}=3.07moles[/tex]
[tex]2C_8H_{18}+25O_2(g)\rightarrow 16CO_2+18H_2O[/tex]
According to stoichiometry :
As 2 moles of octane give = 16 moles of [tex]CO_2[/tex]
Thus 3.07 moles of octane will give =[tex]\frac{16}{2}\times 3.07=24.6moles[/tex] of [tex]CO_2[/tex]
Mass of [tex]CO_2=moles\times {\text {Molar mass}}=24.6moles\times 44g/mol=1082g[/tex]
Thus 1082 g of carbon dioxide are produced for every 350 grams of octane reacted in the engine
