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Given a brick shown above and its length, width, and height
are 10.0cm, 2.00cm, and 5.00cm respectively. The pressure
exerted by the brick on the floor is different when the brick is
placed in different ways. If the minimum pressure exerted by
the brick on the floor is 100.0 Pa, what is the forced exerted on
the floor in newtons (N)?

Respuesta :

xero099

Answer:

[tex]0.1\,N\leq F \leq 0.5\,N[/tex]

Step-by-step explanation:

There are three different values for the force exerted on the floor, which is the product of the force and the cross section area:

Case 1

[tex]F_{1} = (100\,Pa)\cdot (0.1\,m)\cdot (0.05\,m)[/tex]

[tex]F_{1} = 0.5\,N[/tex]

Case 2

[tex]F_{2} = (100\,Pa)\cdot (0.1\,m)\cdot (0.02\,m)[/tex]

[tex]F_{2} = 0.2\,N[/tex]

Case 3

[tex]F_{3} = (100\,Pa)\cdot (0.02\,m)\cdot (0.05\,m)[/tex]

[tex]F_{3} = 0.1\,N[/tex]

Force corresponds to the following interval:

[tex]0.1\,N\leq F \leq 0.5\,N[/tex]

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