What is the area of the parallelogram plotted in the Coordinate Plan in square units? (Only include value! Don't include the word phrase "Squared Units.)
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Answer:
Step-by-step explanation:
D (-2,4) C(-2,-4)
[tex]DC=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}\\\\ =\sqrt{(-2-[-2])^{2}+(-4-4)^{2}}\\\\=\sqrt{(-2+2)^{2}+(-8)^{2}}\\\\ =\sqrt{0+64}\\\\ =\sqrt{64}\\\\=8[/tex]
Base = 8
Height (h)= 3
Area of parallelogram = b*h = 8*3 = 24