Question
A manufacturer is interested in the output voltage of a power supply used in a PC. Output voltage is assumed to be normally distributed, with standard deviation 0.25 Volts, and the manufacturer wishes to test H0: μ = 5 Volts against H1: μ ≠ 5 Volts, using n = 8 units. If the sample mean is x¯¯=4.85 what can you say about the population mean with a=0.05 significance level ?

Respuesta :

Answer:

The population mean is 5 volts

Step-by-step explanation:

Output voltage is assumed to be normally distributed, with standard deviation 0.25 Volts

s=0.25

n = 8

[tex]H_0:\mu = 5\\H_a:\mu \neq 5[/tex]

Sample mean = [tex]\bar{x}=4.85[/tex]

Since n < 30 and population standard deviation is unknown

So, we will use t test

Formula : [tex]t = \frac{x-\mu}{\frac{s}{\sqrt{n}}}[/tex]

[tex]t = \frac{4.85-5}{\frac{0.25}{\sqrt{8}}}[/tex]

t=-1.69

Refer the t table for p value

Degree of freedom = n-1 = 8-1 = 7

So,[tex]t_{(df,\alpha)}=t_{7,0.05}=2.365[/tex]

P value >α

So, We are failed to reject null hypothesis

Hence The population mean is 5 volts