3w-4z=8
2w+3z=-6
A. w=0
z=2
B. w=-2
z=0
C. w=-2
z=-2
D. w=0
z=-2
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The solution for the given system of equation is w = 0 and z = -2.
A system of equations is a collection of two or more equations with a same set of unknowns. For a system to have a unique solution, the number of equations must equal the number of unknowns.
For the given situation,
The equations are
3w-4z=8 -------- (1)
2w+3z=-6 -------(2)
The solution for the above equation,
Multiply the equation 1 by 2,
[tex]6w-8z=16[/tex] --------- (3)
Multiply the equation 2 by 3,
[tex]6w+9z=-18[/tex] --------(4)
Now solve equation 3 and 4 to get,
⇒ [tex]-17z=34[/tex]
⇒ [tex]z=-2[/tex]
Now substitute the value of z in equation 1,
⇒ [tex]3w-4(-2)=8[/tex]
⇒ [tex]3w=0[/tex]
⇒ [tex]w=0[/tex]
Hence we can conclude that the solution for the given system of equation is w = 0 and z = -2.
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