Answer:
[tex]8.065 * 10^{22}[/tex] atoms of Ca.
Explanation:
Basic stoich question:
First the reaction is [tex]3Ca_{(s)} +Ni_2(SO_4)_{3(aq)} --> 3CaSO_{4(aq)} + 2Ni_{(s)}[/tex]
Converting grams to moles: [tex]\frac{5.24g}{58.69g/mol} = 0.0892826 moles.[/tex]
Notice the mole ratio. For every 2 Ni produced, 3 Ca was used.
[tex]0.08928267166 moles * \frac{3}{2} = 0.133924 moles[/tex] of Ca.
There are [tex]6.022*10^{23}[/tex] atoms in a mole.
Thus, multiplying them together = [tex]8.065 * 10^{22}[/tex] atoms
