Determine angle B by using the law of sines. Please help, thank you!
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Answer:
B=36.97
Step-by-step explanation:
non-right triangle
c/sin C = b/ sin B
[tex]\frac{25}{sin(110)} =\frac{16}{sinB}[/tex]
cross multiply to isolate sinB
25sinB=16sin(110)
divide by 25 and isolate angle B by arccos or sin^-1
B=sin^1 ([tex]\frac{16sin(110)}{25}[/tex])
B= 36.97