Answer:
The greater the length, the greater the period. Or vice versa
Explanation:
T = 2π * √(L/g)
Given that T = 1s , g = 9.8m/s^2 , π = 3.14
1 = 2× 3.14 √(L/9.8)
1 = 6.28 ×L /9.8
L= 9.8/6.28
L= 1.56m
When T = 1.5s
1.5 = 2×3.14√(L/9.8)
1.5^2 = 6.28×L/9.8
2.25 = 6.28L/9.8
2.25×9.8 = 6.28L
22.05 = 6.28L
L = 22.05/6.28
L = 3.51m
From the above mathematical solution, it is clear that the greater the length, the greater the period. Or vice versa
