Answer:
10.5
Step-by-step explanation:
\text{SOH-CAH-TOA}
SOH-CAH-TOA
\tan V = \frac{\text{opposite}}{\text{adjacent}}=\frac{15}{81}
tanV=
adjacent
opposite
=
81
15
\tan V = \frac{15}{81}
tanV=
81
15
V=\tan^{-1}(\frac{15}{81})
V=tan
−1
(
81
15
)
V=10.4915\approx 10.5^{\circ}
V=10.4915≈10.5
∘
Type into calculator and round to the nearest tenth of a degree.
V
W
X
81
15
(adjacent to ∠V)
(opp. of ∠V)
(hypotenuse)
10.5°
