enemene
contestada

PLEASE HELP - A student stands 100m in front of a large smooth wall and claps loudly. Another student figures out the time for the sound to travel to the wall and back. If the sound takes 0.58s for the sound to leave and return, what is the speed of the sound?

Respuesta :

AL2006

Speed = distance / time

In this experiment, the distance is 100m TO the wall and another 100m BACK from the wall so he can hear the echo.

Speed = (200 m) / (0.58 s)

Speed = 344.8 m/s

onyebuchinnaji

The speed of the sound for the given distance and time of travel is 344.83 m/s.

The given parameters;

  • distance between the student and the wall, d = 100 m
  • time to receive the sound, t = 0.58 s

The speed of the sound is determined by applying the principle of echo, as shown below;

[tex]v = \frac{2d}{t}[/tex]

where;

  • v is the speed of the sound
  • t is the time to receive the sound
  • 2d is the distance to and fro of the sound

[tex]v = \frac{2 \times 100}{0.58} \\\\v = 344.83 \ m/s[/tex]

Thus, the speed of the sound for the given distance and time of travel is 344.83 m/s.

Learn more here:https://brainly.com/question/10063317

Otras preguntas