Answer:
[273.917;400783]
Step-by-step explanation:
Hello!
You have to estimate the mean level of carbon monoxide in the facility by making a 99% CI.
The variable is
X: carbon monoxide level measured by one detector.
X≈N(μ;σ²)
346.6, 343.2, 305.5, 354.1
n= 4
X[bar]= 337.35
S= 21.72
Since the variable is approximately normal and you don't know the value of the population variance, you have to use the t-statistic:
[X[bar] ± [tex]t_{n-1;1-\alpha /2}[/tex] * [tex]\frac{S}{\sqrt{n} }[/tex]]
[tex]t_{n-1;1-\alpha /2}= t_{3;0.995}= 5.841[/tex]
[337.35 ± 5.841 * [tex]\frac{21.72}{\sqrt{4} }[/tex]]
[273.917;400783]
Using a 99% confidence level you'd expect that the population means of carbon monoxide in the facility.
I hope you have a SUPER day!
