Answer:
Specific heat capacity (c) = 1.7306J/g°C
Explanation:
Q = 9.54kJ = 9540J
Mass of the substance (m) = 225.0g
Initial temperature (T1) = 21.5°C
Final temperature (T2) = 46°C
Specific heat capacity of the substance (c)= ?
Heat energy (Q) = mc∇T
Q = heat energy in joules
M = mass in grams
c = specific heat capacity
∇T = change in temperature = T2 - T1
Q = mc∇T
Q = mc (T2 - T1)
9540 = 225 * c * (46 - 21.5)
9540 = 225c * 24.5
9540 = 5512.5c
c = 9540 / 5512.5
c = 1.7306J/g°C
Specific heat capacity of the substance is 1.7306J/g°C
