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P2: A 10 kg wheel in the shape of a disk with a radius of 35 cm is mounted on frictionless bearings. An ideal string is wrapped many times around the circumference of the wheel, and attached to a 12 kg mass. At t = 0, the mass is released with zero initial velocity. Please answer each of the following questions a) What is the velocity of the mass after it has descended by 2.00 meters b) What is the tension in the string?

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kaancceylan

Answer:

A) 2m/s2   B) 20N

Explanation:

Since the bearings are frictionless and the string is ideal, there won't be any force lost to the friction. The 12 kg mass will have a force of m.g when it is released. We can take the value of g as 10m/s2 if the answer does not have to be exact or 9.81 m/s2 otherwise. The force will be F = 12.10 = 120 N.

If we subtract this from the gravitational force that the 10 kg mass has, we have 20 N in the upwards direction. From the formula F = m.a, we can calculate the acceleration as (20N = 10.a) 2m/s2.

Since the masses are not at an angle and parallel to each other, the tension in the string is equal to the difference of the two forces which is 20N.

I hope this answer helps.

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