1. Mary has a mass of 40 kg and sprints at 1 m/s. How much kinetic energy does she have?

2. Roberto has twice the mass his sister Mary has (see above) but runs at the same velocity as Mary. Will his kinetic energy be twice as much? Show your work.


What happens to Roberto’s kinetic energy when he runs twice as fast?


3. Use the kinetic energy formula KE = 0.5 mv2 to complete the practice problems below. Remember, 1 J = 1 kg ∙ m2 /s2 . Also, velocity is v 2 = KE / (0.5 x m), and mass is m = KE / (0.5 v2 ).

4. What is the kinetic energy of a 150 kg object that is moving at a speed of 15 m/s?


5. An object has a kinetic energy of 500 J and a mass of 30 kg. How fast is the object moving?


6. An object moving with a speed of 5 m/s has a kinetic energy of 100 J. What is the mass of the object?


7. What is the kinetic energy of a 1,200 kg object that is moving at a speed of 24 m/s?




Please help ASAP :(

Respuesta :

Answer:

1. Mary has 20 joules of Kinetic energy

2. Yes his kinetic energy be twice as much

3. If Roberto runs twice as fast, his Kinetic energy will be 4 times as much

4. 16875 Joules

5. 5.77 m/s

6. 8 kg

7. 345600 J

Explanation:

The formula for Kinetic Energy is given as [tex]KE= 0.5\times m \times v^{2}[/tex]

We will apply this in solving all the problems below using the parameters provided by each problem.

1. Mary's Kinetic Energy will be equal to [tex]0.5 \times 40 \times 1^{2}=20joules[/tex]

2a. If Roberto has twice Mary's mass, his mass will be 80 kg.

His K.E will be [tex]KE= 0.5\times 80 \times 1^{2}= 40 joules[/tex]

2b. If Roberto runs twice as fast, his kinetic energy will be [tex]KE= 0.5\times 80 \times 2^{2}= 160 joules[/tex]. This is four times its initial value

4. [tex]KE= 0.5\times 150 \times 15^{2}= 16875 joules[/tex]

5. [tex]v=\sqrt{\frac{500}{0.5 \times 30}}=5.77m/s[/tex]

6. [tex]mass, m = \frac{100}{0.5 \times 5^{2}}= 8kg[/tex]

7. [tex]KE= 0.5\times 1200 \times 24^{2}= 345600 joules[/tex]