Respuesta :
Answer:
See explanation below
Explanation:
In order to solve this, you first need to fill out the blank spaces. This is an experiment and that data is required to solve the questions below. However, I manage to find the same question and the required data is the following:
a) average number of drops in 1 mL: 49
b) volume of 1 drop: 0.0204 mL
c) diameter of water surface: 13.5
d) area of water surface: 12.5
e) number of drop to create a monolayer: 8
With these data we can calculate the whole data of this.
1. grams of stearic acid per drop
To do this, we have the concentration of stearic acid, and the volume of 1 drop, so we can calculate the mass:
m = C * V
m = 0.11 g/L * 0.0204 mL * 1 L / 1000 mL
m = 2.244x10⁻⁶ g
2. grams to make the monolayer
In this case, we know how many drops are needed to make a monolayer, and we also have the volume for every drop, so, we will do the same procedure of 1:
m = 0.11 * 8 * 0.0204 / 1000
m = 1.79x10⁻⁵ g
3. volume of stearic acid
In this case, we use the expression of density to calculate the volume so:
d = m/V --------> V = m/d
V = 1.79x10⁻⁵ / 0.85
V = 2.11x10⁻⁵ mL
4. Thickness of the monolayer
We have the volume and the area is above, so replacing in the given formula:
L = V/A
L = 2.11x10⁻⁵ / 12.5
L = 1.69x10⁻⁶ cm
5. Thickness in angstrom
The conversion for cm to Angstroms is the following:
1 cm ----> 1x10⁸ A
So the given centimeters are:
1.69x10⁻⁶ * 1x10⁸
