A sociologist is studying the effect of having children within the first two years of marriage on the divorce rate. Using hospital birth records, she selects a random sample of 200 couples who had a child within the first two years of marriage. Following up on these couples, she finds that 80 couples are divorced within five years. A 90% confidence interval for the proportion of couples who had a child within the first two years of marriage and are divorced within five years is

Respuesta :

Answer:

90% confidence interval for the proportion of couples who had a child within the first two years of marriage and are divorced within five years is [0.34 , 0.46].

Step-by-step explanation:

We are given that a sociologist selects a random sample of 200 couples who had a child within the first two years of marriage.

Following up on these couples, she finds that 80 couples are divorced within five years.

Firstly, the pivotal quantity for 90% confidence interval for the population proportion is given by;

                               P.Q. =  [tex]\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex]  ~ N(0,1)

where, [tex]\hat p[/tex] = sample proportion of couples who are divorced within five years =  [tex]\frac{80}{200}[/tex]  = 0.40

n = sample of couples who had a child within the first two years of marriage = 200

p = population proportion of couples who had a child within the first two years of marriage and are divorced within five years

Here for constructing 90% confidence interval we have used One-sample z proportion statistics.

So, 90% confidence interval for the population proportion, p is ;

P(-1.645 < N(0,1) < 1.645) = 0.90  {As the critical value of z at 5% level

                                                      of significance are -1.645 & 1.645}  

P(-1.645 < [tex]\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] < 1.645) = 0.90

P( [tex]-1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] < [tex]{\hat p-p}[/tex] < [tex]1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] ) = 0.90

P( [tex]\hat p-1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] < p < [tex]\hat p+1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] ) = 0.90

90% confidence interval for p = [[tex]\hat p-1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex],[tex]\hat p+1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex]]

= [ [tex]0.40-1.645 \times {\sqrt{\frac{0.40(1-0.40)}{200} } }[/tex] , [tex]0.40+1.645 \times {\sqrt{\frac{0.40(1-0.40)}{200} } }[/tex] ]

 = [0.34 , 0.46]

Therefore, 90% confidence interval for the proportion of couples who had a child within the first two years of marriage and are divorced within five years is [0.34 , 0.46].