Answer:
The specific heat of the metal is 0.0132 J g^-1 °K^-1
Explanation:
The sample of metal absorbs 180.8 J of heat.
Mass of the metal = 22.44 g
Temperature increase = Final temperature - initial temperature
change in temperature = (45 + 273 K) - (21.1 + 273 K) = 318 + 294.1 = 612.1 K
Specific heat of the metal = ?
When raising the temperature of a substance, the heat absorbed is calculated using:
H = m c ΔT
Rearranging and making c the sunject of the formula, we obtain:
c = H / m ΔT
c = 180.8 J / 22.44 g * 612.1 K
c = 180.8 J / 13735.524 g K
c = 0.0132 J g^-1 °K^-1
The specific heat of the metal is 0.0132 J g^-1 °K^-1
